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Crosswords and other puzzles

For discussion of all forms of mental gymnastics, especially that baffling final clue

Message board > Crosswords and other puzzles 121 to 130 of 153
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by Mike - Wed 19th Oct 2005, 1:58pm
jpd said: I walk one mile South, one mile East and one mile North and end up where I started. Where am I?
I hope you're expecting more than one possible answer to this...
by jpd - Wed 19th Oct 2005, 1:45pm
mjb said: £1.20, £1.25, £1.50, £3.16
Is the right answer. (Out of interest, how long did it take you?)

I walk one mile South, one mile East and one mile North and end up where I started. Where am I?

(obviously don't answer if I've posed this one to you before)
by mjb - Wed 19th Oct 2005, 1:25pm
jpd said: Obviously I meant a magical flying pen.
£1.20, £1.25, £1.50, £3.16
by Tom C - Wed 19th Oct 2005, 1:02pm
jpd said: This one's a bit harder :-)

I buy four items in a supermarker. Both the sum and product of their values is £7.11. What are their individual values?
As Fitz said, "two packs of sausages constitutes one item", so i don't think this has a solution.
by jpd - Wed 19th Oct 2005, 9:28am
jpd said: ...supermarker...
Obviously I meant a shop in which you can buy all manner of groceries, not a magical flying pen.
by jpd - Wed 19th Oct 2005, 9:22am
Slacker said: BBAB?
This one's a bit harder :-)

I buy four items in a supermarker. Both the sum and product of their values is £7.11. What are their individual values?
by mjb - Wed 19th Oct 2005, 8:59am
jpd said: Answer this multi-choice exam:
BBAB seems to work.
by Slacker - Wed 19th Oct 2005, 8:57am
BBAB?
by jpd - Wed 19th Oct 2005, 7:59am
Bored Lilie said: If so, I make it 7..? I need to do some real work, and/or get a life :)
Is the right answer.

Doing work and getting a life are not allowed. Answer this multi-choice exam:

1. The first question with A as the correct answer is:

    A. 2
    B. 3
    C. 4 

2. Which answer appears most often:

    A. C
    B. B
    C. A 

3. The answer to Question 1 is:

    A. B
    B. A
    C. C 

4. The answer which appears least is:

    A. A
    B. C
    C. B 
by Richard - Wed 19th Oct 2005, 1:20am
Bored Lilie said: If so, I make it 7..? I need to do some real work, and/or get a life :)
If all of the relations have to be there, then I get 7 as well.

Man 1 and Woman 2 are married, and have a son, Man 3 who marries Woman 4. Man 3 and Woman 4 have 3 children - 2 girls, 5 and 6 and a boy, 7.

Man 1 is a grandfather to 5,6&7 (1 grandfather)
Woman 2 is grandmother to 5,6&7 (1 grandmother)

Man 1 is the father of 3. Man 3 is father of 5,6&7 (2 fathers)
Woman 2 is the mother of 3, Woman 4 is mother of 5,6&7 (2 mothers)
3 is the child of 1&2, 5,6&7 are the children of 3&4 (4 children)
5,6&7 are grandchildren of 1&2 (3 grandchildren)
5 is the brother of 6&7 (1 brother)
6&7 are the sisters of 5 (2 sisters)
3 is the son of 1&2, 5 is the son of 3&4 (2 sons)
6&7 are the daughers of 3&4 (2 daughters)
4's mother-in-law is 2 (1 mother-in-law)
4's father-in-law is 1 (1 father-in-law)
4 is the daughter-in-law of 1&2 (1 daughter-in-law).

That's all of the requirements met. Can it be done in a better way?

If you actually had 23 people, all related closely, then presumably, you'd have more than the required number in each category. There must be a maximum number of closely related people.....

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