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Crosswords and other puzzles
For discussion of all forms of mental gymnastics, especially that baffling final clue
Message board > Crosswords and other puzzles | 124 to 133 of 153 |
by Tom C - Wed 19th Oct 2005, 1:02pm | ||
jpd said: This one's a bit harder :-) As Fitz said, "two packs of sausages constitutes one item", so i don't think this has a solution.I buy four items in a supermarker. Both the sum and product of their values is £7.11. What are their individual values? | ||
by jpd - Wed 19th Oct 2005, 9:28am | ||
jpd said: ...supermarker... Obviously I meant a shop in which you can buy all manner of groceries, not a magical flying pen. | ||
by jpd - Wed 19th Oct 2005, 9:22am | ||
Slacker said: BBAB? This one's a bit harder :-)I buy four items in a supermarker. Both the sum and product of their values is £7.11. What are their individual values? | ||
by mjb - Wed 19th Oct 2005, 8:59am | ||
jpd said: Answer this multi-choice exam: BBAB seems to work. | ||
by Slacker - Wed 19th Oct 2005, 8:57am | ||
BBAB? | ||
by jpd - Wed 19th Oct 2005, 7:59am | ||
Bored Lilie said: If so, I make it 7..? I need to do some real work, and/or get a life :) Is the right answer.Doing work and getting a life are not allowed. Answer this multi-choice exam: 1. The first question with A as the correct answer is: A. 2 B. 3 C. 4 2. Which answer appears most often: A. C B. B C. A 3. The answer to Question 1 is: A. B B. A C. C 4. The answer which appears least is: A. A B. C C. B | ||
by Richard - Wed 19th Oct 2005, 1:20am | ||
Bored Lilie said: If so, I make it 7..? I need to do some real work, and/or get a life :) If all of the relations have to be there, then I get 7 as well.Man 1 and Woman 2 are married, and have a son, Man 3 who marries Woman 4. Man 3 and Woman 4 have 3 children - 2 girls, 5 and 6 and a boy, 7. Man 1 is a grandfather to 5,6&7 (1 grandfather) Woman 2 is grandmother to 5,6&7 (1 grandmother) Man 1 is the father of 3. Man 3 is father of 5,6&7 (2 fathers) Woman 2 is the mother of 3, Woman 4 is mother of 5,6&7 (2 mothers) 3 is the child of 1&2, 5,6&7 are the children of 3&4 (4 children) 5,6&7 are grandchildren of 1&2 (3 grandchildren) 5 is the brother of 6&7 (1 brother) 6&7 are the sisters of 5 (2 sisters) 3 is the son of 1&2, 5 is the son of 3&4 (2 sons) 6&7 are the daughers of 3&4 (2 daughters) 4's mother-in-law is 2 (1 mother-in-law) 4's father-in-law is 1 (1 father-in-law) 4 is the daughter-in-law of 1&2 (1 daughter-in-law). That's all of the requirements met. Can it be done in a better way? If you actually had 23 people, all related closely, then presumably, you'd have more than the required number in each category. There must be a maximum number of closely related people..... | ||
by Bored Lilie - Tue 18th Oct 2005, 9:37pm | ||
Bryn said: If not then I guess you only need two women and two men who can cover everything between them. If so, I make it 7..? I need to do some real work, and/or get a life :) | ||
by Bryn - Tue 18th Oct 2005, 5:07pm | ||
A certain family party consisted of 1 grandfather, 1 grandmother, 2 fathers, 2 mothers, 4 children, 3 grandchildren, 1 brother, 2 sisters, 2 sons, 2 daughters, 1 father-in-law, 1 mother-in-law, and 1 daughter-in-law. A total of 23 people, you might think, but, no. What is the minimum number of people here? Does the person to whom that relationship corresponds have to be there as well? For example, does the grandfather's grandchild have to be there? If not then I guess you only need two women and two men who can cover everything between them. | ||
by jpd - Tue 18th Oct 2005, 4:53pm | ||
mjb said: AFAICT, it's the Coffee-drinking German in the Green House Is the right answer.A certain family party consisted of 1 grandfather, 1 grandmother, 2 fathers, 2 mothers, 4 children, 3 grandchildren, 1 brother, 2 sisters, 2 sons, 2 daughters, 1 father-in-law, 1 mother-in-law, and 1 daughter-in-law. A total of 23 people, you might think, but, no. What is the minimum number of people here? |
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